2019-05-02 07:22:10 +03:00
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// 中介者模式(mediator pattern)
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2019-05-02 13:16:11 +03:00
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// 当两个对象存在复杂的依赖关系时,考虑增加一个中介者使之解耦,使他们不需要进行显式的引用.
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2019-05-02 07:22:10 +03:00
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// 但问题在于中介本身会去实现复杂的逻辑,进而导致中介者变得复杂臃肿难以维护.
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//
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2019-05-02 13:16:11 +03:00
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// 这里是竞价的例子.
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2019-05-02 07:22:10 +03:00
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// 参与竞价的玩家只需要向中介出价就可以知道是否能买到商品,由中介确定谁的出价高
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package main
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import (
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"log"
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"math/rand"
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"time"
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)
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// buyer 之间通过中介进行引用
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type Buyer struct {
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m *Mediator
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Name string// unique
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}
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func (b Buyer)Bid(price int){
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if p ,ok := b.m.isMaxPrice(b ,price);ok{
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log.Println(b.Name ,"are in lead temporarily with" ,p)
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}else{
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log.Println(b.Name ,"lose with" ,p)
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}
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}
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type Mediator struct {
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Buyers map[Buyer]int
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MaxPrice int
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MaxPriceBuyer Buyer
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}
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func (m *Mediator)isMaxPrice(b Buyer ,price int)(int ,bool){
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if b.Name == m.MaxPriceBuyer.Name{
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return m.MaxPrice ,true
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}
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m.Buyers[b] = price
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for k ,v := range m.Buyers{
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if v > m.MaxPrice{
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m.MaxPrice = v
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m.MaxPriceBuyer = k
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}
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}
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if b.Name == m.MaxPriceBuyer.Name{
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return price ,true
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}
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return price ,false
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}
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func main(){
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m := &Mediator{
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make(map[Buyer]int),
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0,
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Buyer{},
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}
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icg := Buyer{m ,"icg"}
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nyn := Buyer{m ,"nyn"}
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rand.Seed(time.Now().UnixNano())
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for i:=0 ;i<3 ;i++{
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icg.Bid(rand.Intn(10000))
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nyn.Bid(rand.Intn(10000))
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}
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// output:
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/*
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2019/05/02 12:19:52 icg are in lead temporarily with 1024
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2019/05/02 12:19:52 nyn are in lead temporarily with 4232
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2019/05/02 12:19:52 icg are in lead temporarily with 6412
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2019/05/02 12:19:52 nyn are in lead temporarily with 6747
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2019/05/02 12:19:52 icg lose with 4951
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2019/05/02 12:19:52 nyn are in lead temporarily with 6747
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*/
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}
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