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A nicer way of detecting the platform

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Inspired by https://github.com/doctrine/doctrine2/blob/master/tests/Doctrine/Tests/ORM/Functional/DatabaseDriverTest.php#L188
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flip111 2013-09-13 16:35:34 +02:00
parent a190dad0b1
commit 67dd32d9fb
1 changed files with 1 additions and 1 deletions
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2
tests/Doctrine/Tests/ORM/Functional/Ticket/DDC719Test.php
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@ -19,7 +19,7 @@ class DDC719Test extends \Doctrine\Tests\OrmFunctionalTestCase
{ {
$q = $this->_em->createQuery('SELECT g, c FROM Doctrine\Tests\ORM\Functional\Ticket\DDC719Group g LEFT JOIN g.children c WHERE g.parents IS EMPTY'); $q = $this->_em->createQuery('SELECT g, c FROM Doctrine\Tests\ORM\Functional\Ticket\DDC719Group g LEFT JOIN g.children c WHERE g.parents IS EMPTY');
if ($this->_em->getConnection()->getDatabasePlatform()->getName() === 'mssql') { if ($this->_em->getConnection()->getDatabasePlatform() instanceof SQLServerPlatform) {
$referenceSQL = 'SELECT g0_.name AS name0, g0_.description AS description1, g0_.id AS id2, g1_.name AS name3, g1_.description AS description4, g1_.id AS id5 FROM groups g0_ with (nolock) LEFT JOIN groups_groups g2_ ON g0_.id = g2_.parent_id LEFT JOIN groups g1_ ON g1_.id = g2_.child_id WHERE (SELECT COUNT(*) FROM groups_groups g3_ WHERE g3_.child_id = g0_.id) = 0'; $referenceSQL = 'SELECT g0_.name AS name0, g0_.description AS description1, g0_.id AS id2, g1_.name AS name3, g1_.description AS description4, g1_.id AS id5 FROM groups g0_ with (nolock) LEFT JOIN groups_groups g2_ ON g0_.id = g2_.parent_id LEFT JOIN groups g1_ ON g1_.id = g2_.child_id WHERE (SELECT COUNT(*) FROM groups_groups g3_ WHERE g3_.child_id = g0_.id) = 0';
} else { } else {
$referenceSQL = 'SELECT g0_.name AS name0, g0_.description AS description1, g0_.id AS id2, g1_.name AS name3, g1_.description AS description4, g1_.id AS id5 FROM groups g0_ LEFT JOIN groups_groups g2_ ON g0_.id = g2_.parent_id LEFT JOIN groups g1_ ON g1_.id = g2_.child_id WHERE (SELECT COUNT(*) FROM groups_groups g3_ WHERE g3_.child_id = g0_.id) = 0'; $referenceSQL = 'SELECT g0_.name AS name0, g0_.description AS description1, g0_.id AS id2, g1_.name AS name3, g1_.description AS description4, g1_.id AS id5 FROM groups g0_ LEFT JOIN groups_groups g2_ ON g0_.id = g2_.parent_id LEFT JOIN groups g1_ ON g1_.id = g2_.child_id WHERE (SELECT COUNT(*) FROM groups_groups g3_ WHERE g3_.child_id = g0_.id) = 0';